V\u1eady kh\u00e1i ni\u1ec7m c\u1ee7a c\u00e1ch \u0111\u00e1nh l\u00f4 n\u00e0y l\u00e0 nh\u01b0 th\u1ebf n\u00e0o? N\u1ebfu anh em l\u00e0 ng\u01b0\u1eddi ch\u01b0a c\u00f3 kinh nghi\u1ec7m v\u00e0 ch\u01b0a hi\u1ec3u r\u00f5 v\u1ec1 thu\u1eadt ng\u1eef n\u00e0y th\u00ec h\u00e3y tham kh\u1ea3o qua b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y c\u1ee7a ch\u00fang t\u00f4i <\/b>nh\u00e9.<\/p>\n Bao l\u00f4<\/strong> l\u00e0 m\u1ed9t thu\u1eadt ng\u1eef xu\u1ea5t ph\u00e1t t\u1eeb Mi\u1ec1n Trung v\u00e0 hi\u1ec7n nay n\u00f3 \u0111\u00e3 \u0111\u01b0\u1ee3c ph\u1ed5 bi\u1ebfn v\u1edbi t\u1ea5t c\u1ea3 anh em ch\u01a1i l\u00f4 \u0111\u1ec1 tr\u00ean kh\u1eafp c\u1ea3 n\u01b0\u1edbc. Bao l\u00f4 t\u1ee9c l\u00e0 \u0111\u00e1nh 2 s\u1ed1 cu\u1ed1i c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 h\u1eb1ng ng\u00e0y (27 gi\u1ea3i \u0111\u1ed1i v\u1edbi KQXS mi\u1ec1n B\u1eafc, 18 gi\u1ea3i \u0111\u1ed1i v\u1edbi KQXS Mi\u1ec1n Nam v\u00e0 Trung).<\/p>\n V\u00ed d\u1ee5: T\u00f4i \u0111\u00e1nh bao l\u00f4 s\u1ed1 10 \u0111\u00e0i Mi\u1ec1n B\u1eafc t\u1ee9c l\u00e0 \u0111\u1eb7t 1.000\u0111 th\u00ec t\u00f4i s\u1ebd ph\u1ea3i thanh to\u00e1n 27.000\u0111. N\u1ebfu l\u00f4 10 v\u1ec1 1 trong 27 s\u1ed1 c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i Mi\u1ec1n B\u1eafc th\u00ec t\u00f4i tr\u00fang. Tr\u01b0\u1eddng h\u1ee3p con 10 v\u1ec1 2 l\u1ea7n th\u00ec t\u00f4i tr\u00fang 2 nh\u00e1y, 3 l\u1ea7n l\u00e0 3 nh\u00e1y t\u1ee9c l\u00e0 x2 v\u00e0 x3 s\u1ed1 ti\u1ec1n th\u01b0\u1edfng.<\/p>\n Bao l\u00f4 l\u00e0 g\u00ec?<\/p>\n<\/div>\n Bao l\u00f4 Mi\u1ec1n B\u1eafc: Hay c\u00f2n g\u1ecdi l\u00e0 b\u1ea1ch th\u1ee7 l\u00f4, ng\u01b0\u1eddi ch\u01a1i s\u1ebd soi c\u1ea7u 1 con b\u1ea1ch th\u1ee7 l\u00f4 ho\u1eb7c nhi\u1ec1u con \u0111\u1ec3 d\u1ef1 \u0111o\u00e1n con s\u1ed1 s\u1ebd v\u1ec1 trong ng\u00e0y h\u00f4m \u0111\u00f3.<\/p>\n Bao l\u00f4 Mi\u1ec1n Nam, Mi\u1ec1n Trung: Th\u1eafng hay thua l\u00e0 d\u1ef1a v\u00e0o 2 s\u1ed1 cu\u1ed1i c\u1ee7a k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y h\u00f4m \u0111\u00f3. N\u1ebfu con l\u00f4 c\u1ee7a anh em tr\u00f9ng th\u00ec anh em th\u1eafng.<\/p>\n M\u1ed7i v\u00f9ng mi\u1ec1n s\u1ebd c\u00f3 m\u1ed9t h\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 \u0111\u1ec1<\/strong><\/span><\/span> kh\u00e1c nhau, ch\u00ednh v\u00ec th\u1ebf anh em c\u1ea7n ph\u1ea3i t\u00ecm hi\u1ec3u r\u00f5 \u0111\u1ec3 tr\u00e1nh nh\u1ea7m l\u1eabn.C\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n C\u00e1ch \u0111\u00e1nh l\u00f4.<\/p>\n<\/div>\n T\u1ef7 l\u1ec7 tr\u00fang c\u01b0\u1ee3c c\u1ee7a h\u00ecnh th\u1ee9c ch\u01a1i bao l\u00f4 tuy kh\u00f4ng cao b\u1eb1ng ch\u01a1i \u0111\u1ec1, nh\u01b0ng v\u1edbi x\u00e1c su\u1ea5t d\u1ec5 tr\u00fang h\u01a1n n\u00ean ti\u1ec1n th\u01b0\u1edfng ch\u1eafc ch\u1eafn s\u1ebd kh\u00f4ng cao b\u1eb1ng. Nh\u01b0ng \u0111\u00e2y c\u0169ng l\u00e0 m\u1ed9t h\u00ecnh th\u1ee9c kh\u00e1 thu h\u00fat c\u00e1c anh em l\u00f4 th\u1ee7. T\u00ecm hi\u1ec3u ngay 3 h\u00ecnh th\u1ee9c t\u00ednh ti\u1ec1n bao l\u00f4 c\u1ee7a 3 mi\u1ec1n ngay b\u00ean d\u01b0\u1edbi:<\/p>\n Ch\u01a1i l\u00f4 Mi\u1ec1n B\u1eafc th\u00ec 1 \u0111i\u1ec3m t\u01b0\u01a1ng \u1ee9ng v\u1edbi 23.000 vn\u0111. Tuy nhi\u00ean, \u0111\u1ec3 thu h\u00fat ng\u01b0\u1eddi ch\u01a1i th\u00ec nhi\u1ec1u nh\u00e0 c\u00e1i \u0111\u00e3 gi\u1ea3m s\u1ed1 ti\u1ec1n cho 1 \u0111i\u1ec3m ch\u1ec9 c\u00f2n 21.000 \u2013 22.000 vn\u0111. \u0110\u1ed1i v\u1edbi ti\u1ec1n th\u01b0\u1edfng th\u00ec 1 \u0111i\u1ec3m tr\u00fang gi\u1ea3i s\u1ebd t\u01b0\u01a1ng \u1ee9ng v\u1edbi 80.000 vn\u0111.<\/p>\n V\u00ed d\u1ee5: Anh em \u0111\u00e1nh con l\u00f4 25 v\u1edbi 10 \u0111i\u1ec3m (ti\u1ec1n c\u01b0\u1ee3c: 230.000 vn\u0111), chi\u1ec1u h\u00f4m \u0111\u00f3 con l\u00f4 25 n\u00e0y n\u1ed5 2 nh\u00e1y th\u00ec s\u1ed1 ti\u1ec1n anh em nh\u1eadn \u0111\u01b0\u1ee3c s\u1ebd l\u00e0:<\/p>\n S\u1ed1 \u0111i\u1ec3m c\u01b0\u1ee3c x 80.000 vn\u0111 x s\u1ed1 nh\u00e1y l\u00f4 v\u1ec1 = 10 \u0111i\u1ec3m x 80.000vn\u0111 x 2 = 1.600.000 vn\u0111.<\/strong><\/p>\n Suy ra anh em l\u00e3i: 1.600.000 vn\u0111 \u2013 230.000 vn\u0111 = 1.370.000 vn\u0111.<\/p>\n C\u00e1c c\u00e1ch t\u00ednh ti\u1ec1n th\u01b0\u1edfng kh\u00e1c:<\/p>\n C\u00e1ch t\u00ednh ti\u1ec1n t\u01b0\u01a1ng t\u1ef1 nh\u01b0 Mi\u1ec1n B\u1eafc, ch\u1ec9 kh\u00e1c \u1edf \u0111\u00e2y l\u00e0 gi\u00e1 \u0111i\u1ec3m c\u01b0\u1ee3c th\u1ea5p h\u01a1n, dao \u0111\u1ed9ng t\u1eeb 14.400 \u2013 15.000 vn\u0111 cho 1 \u0111i\u1ec3m \u0111\u00e1nh v\u00e0 tr\u1ea3 th\u01b0\u1edfng c\u0169ng l\u00e0 75.000 \u2013 80.000 vn\u0111.<\/p>\n V\u00ed d\u1ee5: Anh em \u0111\u00e1nh con l\u00f4 25 v\u1edbi 10 \u0111i\u1ec3m (ti\u1ec1n c\u01b0\u1ee3c: 150.000 vn\u0111) v\u00e0 chi\u1ec1u h\u00f4m sau c\u0169ng n\u1ed5 2 nh\u00e1y th\u00ec s\u1ed1 ti\u1ec1n anh em nh\u1eadn \u0111\u01b0\u1ee3c s\u1ebd l\u00e0: 10 \u0111i\u1ec3m x 80.000 vn\u0111 x 2 nh\u00e1y = 1.600.000 vn\u0111.<\/p>\n Nh\u01b0ng kh\u00e1c \u1edf \u0111\u00e2y l\u00e0 s\u1ed1 ti\u1ec1n anh em l\u00e3i s\u1ebd l\u00e0 1.600.000 \u2013 150.000 = 1.450.000 vn\u0111 cao h\u01a1n Mi\u1ec1n B\u1eafc 80.000 vn\u0111.<\/p>\n C\u00e1c c\u00e1ch t\u00ednh ti\u1ec1n th\u01b0\u1edfng kh\u00e1c:<\/p>\n \u1ede mi\u1ec1n Nam th\u00ec c\u0169ng t\u01b0\u01a1ng t\u1ef1 nh\u01b0 mi\u1ec1n Trung v\u1edbi m\u1ee9c c\u01b0\u1ee3c gi\u1ed1ng nhau ( 14.400 \u2013 15.000 vn\u0111) v\u00e0 ti\u1ec1n th\u01b0\u1edfng \u0111\u00e1nh bao l\u00f4 2 s\u1ed1 c\u0169ng nh\u01b0 nhau dao \u0111\u1ed9ng t\u1eeb 75000 \u2013 80.000 vn\u0111.<\/p>\n C\u00e1c c\u00e1ch t\u00ednh ti\u1ec1n th\u01b0\u1edfng kh\u00e1c:<\/p>\n Tr\u00ean \u0111\u00e2y l\u00e0 to\u00e0n b\u1ed9 nh\u1eefng chia s\u1ebb c\u1ee7a t\u00f4i mu\u1ed1n truy\u1ec1n \u0111\u1ea1t \u0111\u1ebfn anh em v\u1ec1 bao l\u00f4<\/strong>. \u0110\u1ec3 \u0111\u00e1nh bao l\u00f4 hi\u1ec7u qu\u1ea3 v\u00e0 \u0103n \u0111\u01b0\u1ee3c nhi\u1ec1u ti\u1ec1n th\u01b0\u1edfng, anh em c\u1ea7n ph\u1ea3i c\u00f3 kinh nghi\u1ec7m soi c\u1ea7u b\u1eaft l\u00f4 hi\u1ec7u qu\u1ea3 th\u00ec t\u1ef7 l\u1ec7 th\u1eafng m\u1edbi cao \u0111\u01b0\u1ee3c.<\/p>\n M\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p \u0111\u01b0\u1ee3c c\u00e1c b\u1eadc b\u1ed1i cho l\u00e0 hi\u1ec7u qu\u1ea3 b\u1eadc nh\u1ea5t m\u00e0 anh em kh\u00f4ng th\u1ec3 kh\u00f4ng bi\u1ebft \u0111\u00f3 ch\u00ednh l\u00e0 soi c\u1ea7u b\u1ea1c nh\u1edb<\/strong><\/span> & Soi c\u1ea7u l\u00f4 tam gi\u00e1c ma thu\u1eadt<\/strong><\/span><\/span>.<\/p>\n c\u00f3 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p m\u00e0 t\u00f4i ngh\u0129 s\u1ebd gi\u00fap anh em r\u1ea5t nhi\u1ec1u trong vi\u1ec7c b\u1eaft \u0111\u01b0\u1ee3c m\u1ed9t con l\u00f4 c\u00f3 t\u1ef7 l\u1ec7 tr\u00fang cao nh\u1ea5t \u0111\u00f3 ch\u00ednh l\u00e0 c\u00e1ch \u0111\u00e1nh<\/p>\n Ch\u00fac anh em may m\u1eafn v\u00e0 th\u00e0nh c\u00f4ng.<\/p>\n<\/article>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\nBao l\u00f4 l\u00e0 g\u00ec?<\/span><\/h2>\n
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Ph\u00e2n lo\u1ea1i bao l\u00f4<\/span><\/h3>\n
C\u00e1c c\u00e1ch \u0111\u00e1nh bao l\u00f4<\/span><\/h2>\n
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\u0110\u00e1nh bao l\u00f4 \u0103n bao nhi\u00eau<\/span><\/h2>\n
1. C\u00e1ch t\u00ednh ti\u1ec1n \u0103n bao l\u00f4 Mi\u1ec1n B\u1eafc<\/span><\/h3>\n
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2. C\u00e1ch t\u00ednh ti\u1ec1n \u0103n bao l\u00f4 Mi\u1ec1n Trung<\/span><\/h3>\n
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3. C\u00e1ch t\u00ednh ti\u1ec1n \u0103n bao l\u00f4 Mi\u1ec1n Nam<\/span><\/h3>\n
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K\u1ebft lu\u1eadn<\/span><\/h2>\n
SOI C\u1ea6U MI\u1ec0N B\u1eaeC CAO C\u1ea4P<\/h3>\n